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What people are asking?

Pranav Satti

Sep 1, 2014

In an equilateral Δ ABC, the side BC is trisected at D. Prove that 9AD2 = 7AB2

In this solution triangle ABC and ACE is taken in place of ABC, ABE should be taken.

Answer (3)

Swetcha

Aug 9, 2013

D,E,F are respectively th mid-points of the sides AB,BC and CA of Î”ABC. Find the ratios of the area of Î”DEF and Î”ABC.

This answer has an image. Please click on the question to read more.

Answer (2)

Vaishali mathur Mathur

Aug 18, 2013

Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of squares of its sides.

This answer has an image. Please click on the question to read more.

Answer (2)

Tonykuttan

Aug 27, 2014

Prove that the area of the equilateral triangle described on the side of a square is half the area of the equilateral triangle describes on its diagonal.

This answer has an image. Please click on the question to read more.

Answer (2)

Harshit

Aug 7, 2013

Prove that the sum of squares of of the sides of a rhombus is equal to the sum of its squares of its diagonals

This answer has an image. Please click on the question to read more.

Answer (3)

Adithyan Sanal

Apr 14, 2015

Prove that in a triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite to the first side is a right angle. 

This answer has an image. Please click on the question to read more.

Answer (2)

Gajaanan Muley

Aug 10, 2013

AD is an altitude of an equilateral triangle ABC. On AD as a base,another equilateral triangle ADE is constructed.Prove that area(ADE):area(ABC)=3:4.

This answer has an image. Please click on the question to read more.

Answer (3)

Nitin Rajda Rajda

Sep 23, 2013

Two trees of heights a and b are p meters apart. Prove that the height of the point of intersection of the lines joining the top of each tree to the foot of the opposite tree is gien by ab/a+b m.

This answer has an image. Please click on the question to read more.

Answer (3)

Rohit

Sep 6, 2014

Two poles having heights of 6m and 11m stand vertically on a plane ground. if the distance between their feet is 12m, Find the distance between their tops.

This answer has an image. Please click on the question to read more.

Answer (2)

Malavika Ramesh

Sep 18, 2014

in a triangle ABC right angled at A, AB=5 cm and AC=12 cm. If AD perpendicular BC then find AD.

This answer has an image. Please click on the question to read more.

Answer (3)

Pranav Satti

Sep 1, 2014

In an equilateral Δ ABC, the side BC is trisected at D. Prove that 9AD2 = 7AB2

In this solution triangle ABC and ACE is taken in place of ABC, ABE should be taken.

Answer (3)

Swetcha

Aug 9, 2013

D,E,F are respectively th mid-points of the sides AB,BC and CA of Î”ABC. Find the ratios of the area of Î”DEF and Î”ABC.

This answer has an image. Please click on the question to read more.

Answer (2)

Vaishali mathur Mathur

Aug 18, 2013

Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of squares of its sides.

This answer has an image. Please click on the question to read more.

Answer (2)

Tonykuttan

Aug 27, 2014

Prove that the area of the equilateral triangle described on the side of a square is half the area of the equilateral triangle describes on its diagonal.

This answer has an image. Please click on the question to read more.

Answer (2)

Harshit

Aug 7, 2013

Prove that the sum of squares of of the sides of a rhombus is equal to the sum of its squares of its diagonals

This answer has an image. Please click on the question to read more.

Answer (3)

Adithyan Sanal

Apr 14, 2015

Prove that in a triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite to the first side is a right angle. 

This answer has an image. Please click on the question to read more.

Answer (2)

Gajaanan Muley

Aug 10, 2013

AD is an altitude of an equilateral triangle ABC. On AD as a base,another equilateral triangle ADE is constructed.Prove that area(ADE):area(ABC)=3:4.

This answer has an image. Please click on the question to read more.

Answer (3)

Nitin Rajda Rajda

Sep 23, 2013

Two trees of heights a and b are p meters apart. Prove that the height of the point of intersection of the lines joining the top of each tree to the foot of the opposite tree is gien by ab/a+b m.

This answer has an image. Please click on the question to read more.

Answer (3)

Rohit

Sep 6, 2014

Two poles having heights of 6m and 11m stand vertically on a plane ground. if the distance between their feet is 12m, Find the distance between their tops.

This answer has an image. Please click on the question to read more.

Answer (2)

Malavika Ramesh

Sep 18, 2014

in a triangle ABC right angled at A, AB=5 cm and AC=12 cm. If AD perpendicular BC then find AD.

This answer has an image. Please click on the question to read more.

Answer (3)

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