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Install NowNeha Vilasi
Aug 19, 2013
Sunitha
Aug 19, 2013
Raj kishore patro
Jul 10, 2013
Mohammed furqaan Hussain
Aug 23, 2013
Meghna deshnur
Aug 5, 2013
Sir,
I have a doubt regarding this question, kindly tell me whether the answer for the question given below is correct?
Q) x3 - 3x2 - 9x - 5
Ans) p(x) = x3 - 3x2 - 9x - 5
Factors of 5 = 1,5,-1,-5
p(1) = 13 - 3 x (1)2 - 9 x (1) - 5
= 1 -3 - 9 - 5
= 1 - 17 = - 16 ≠0
p(-1) = (-1)3 x 3 x (-1)2 - 9 x (-1) -5
= -1 - 3 + 9 - 5 = -9 + 9 = 0
p(-1) =0
∴ (x+1) is a factor of p(x)
p(x) ÷ (x+1)
x3 - 3x2 - 9x - 5 ÷ x + 1
= x2 - 4x - 5
x2 - 4x - 5
x2 - 5x + 1x - 5
= x ( x - 5) + 1 ( x - 5)
= ( x - 5) ( x + 1)
But finally x3 - 3x2 - 9x - 5 = ( x + 1)( x + 1)( x - 5)
Neha Vilasi
Aug 31, 2013
Smritishraddha suresh
Aug 27, 2013
Meghna deshnur
Jul 26, 2013
Given x + y + z = 8 and xy + yz + zx = 20
Consider, x + y + z = 8
Squaring on both sides, we get
(x + y + z)2 = 82
x2 + y2 + z2 +2(xy + yz +zx) = 64
...
Sunil dhikle
Aug 8, 2013
Aakash Prakash
Sep 13, 2013
Neha Vilasi
Aug 19, 2013
Sunitha
Aug 19, 2013
Raj kishore patro
Jul 10, 2013
Mohammed furqaan Hussain
Aug 23, 2013
Meghna deshnur
Aug 5, 2013
Sir,
I have a doubt regarding this question, kindly tell me whether the answer for the question given below is correct?
Q) x3 - 3x2 - 9x - 5
Ans) p(x) = x3 - 3x2 - 9x - 5
Factors of 5 = 1,5,-1,-5
p(1) = 13 - 3 x (1)2 - 9 x (1) - 5
= 1 -3 - 9 - 5
= 1 - 17 = - 16 ≠0
p(-1) = (-1)3 x 3 x (-1)2 - 9 x (-1) -5
= -1 - 3 + 9 - 5 = -9 + 9 = 0
p(-1) =0
∴ (x+1) is a factor of p(x)
p(x) ÷ (x+1)
x3 - 3x2 - 9x - 5 ÷ x + 1
= x2 - 4x - 5
x2 - 4x - 5
x2 - 5x + 1x - 5
= x ( x - 5) + 1 ( x - 5)
= ( x - 5) ( x + 1)
But finally x3 - 3x2 - 9x - 5 = ( x + 1)( x + 1)( x - 5)
Neha Vilasi
Aug 31, 2013
Smritishraddha suresh
Aug 27, 2013
Meghna deshnur
Jul 26, 2013
Given x + y + z = 8 and xy + yz + zx = 20
Consider, x + y + z = 8
Squaring on both sides, we get
(x + y + z)2 = 82
x2 + y2 + z2 +2(xy + yz +zx) = 64
...
Sunil dhikle
Aug 8, 2013
Aakash Prakash
Sep 13, 2013